Срочно!!!!!! поиогите решить

1)

[tex]f(x) = x \sin(x) \\ f'(x) = x' \sin(x) + x (\sin(x)) ' = \\ = \sin(x) + x \cos(x) [/tex]

2)

[tex]g(x) = \frac{ {x}^{2} - 1 }{x + 3} \\ g'(x) = \frac{( {x {}^{2} - 1)'}^{}(x + 3) - (x + 3)'( {x}^{2} - 1) }{(x + 3) {}^{2} } = \\ = \frac{2x(x + 3) - ( {x }^{2} - 1) }{(x + 3) {}^{2} } = \frac{2 {x}^{2} + 6x - {x}^{2} + 1 }{(x + 3) {}^{2} } = \\ = \frac{ {x}^{2} + 6x + 1}{(x + 3) {}^{2} } [/tex]