[tex] 36^{ log_{6}5}+ 10^{1-lg2}- 3^{log_{9}36} [/tex]

[tex]36^{\log_{6}5} + 10^{1 - \lg2} -3^{log_{9}36}\\\\ (6^2)^{\log_{6}5} + \frac{10}{10^{\lg2}} - 3^{log_{3^2}36}\\\\ 6^{2\log_{6}5} + \frac{10}{2} - 3^{\frac{1}{2}log_{3}36}\\\\ 6^{\log_{6}5^2} + \frac{10}{2} - 3^{log_{3}\sqrt{36}}\\\\ 25 + 5 - 6 = \fbox{24} [/tex]