ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ПРИМЕР (╯︵╰,)

1 действие:
[tex] \frac{x - 4}{3 {x}^{2} + 11x - 4} - \frac{16}{16 - {x}^{2} } = \frac{x - 4}{3(x + 4)(x - \frac{1}{3}) } - \frac{16}{(4 - x)(4 + x)} = \frac{x - 4}{(x + 4)(3x - 1)} - \frac{16}{(4 - x)(4 + x)} = \frac{(x - 4)(4 - x) - 16(3x - 1)}{(x + 4)(3x - 1)(4 - x)} = \frac{ - {(x - 4)}^{2} - 48x + 16}{(x + 4)(3x - 1)(4 - x)} = \frac{ - {x}^{2} + 8x - 16 - 48x + 16}{(x + 4)(3x - 1)(4 - x)} = \frac{ - {x}^{2} - 40x}{(x + 4)(3x - 1)(4 - x)} = - \frac{x(x + 40)}{(x + 4)(3x - 1)(4 - x)} = \frac{x(x + 40)}{(x + 4)(x - 4)(3x - 1)} [/tex]
2 действие:
[tex] \frac{x + 40}{ {x}^{3} - 16x } \div ( - \frac{x(x + 40)}{(4 - x)(x + 4)(3x - 1)} ) = \frac{x + 40}{ x( {x}^{2} - 16) } \times \frac{(x - 4)(x + 4)(3x - 1)}{x(x + 40)} = \frac{x + 4}{x(x - 4)(x + 4)} \times \frac{(x - 4)(x + 4)(3x - 1)}{x(x + 40)} = \frac{3x - 1}{ {x}^{2} } [/tex]

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